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Summer 2002
RIGIDITY CALCULATIONS FOR
WALLS WITH OPENINGS

The "Spring 2002 Masonry Chronicles" issue
addressed the design of piers and inherent in it
was rigidity calculation for piers. This issue
basically addressed the rigidity of shear walls in
general, but not the design of shear
walls.
Masonry walls often have
openings in them for doors, windows or openings to
accommodate equipment etc. Calculation of
rigidities for these walls is complex and tedious.
This article provides a background on the rigidity
of walls, the components contributing to it and
influence of openings on rigidity. Approximate
method for calculating rigidity, which is useful
for preliminary design, is also
proposed.
INTRODUCTION
Walls, when subjected to
in-plane lateral loads, undergo deflection. This
deflection is a result of the wall behaving in
flexural mode and shear mode. The prime behavioral
mode is dependent on height to length ratios. Most
walls neither behave in pure flexural mode, nor in
pure shear mode. Their overall behavior is normally
a combination of the two modes.
Wall rigidity is the amount
of force required to deflect the wall by one
unit.
Calculation of rigidity
primarily serves two purposes :
1. distribution of lateral
loads to various lateral load-resisting elements
and 2. to calculate overall deflection (drift) of
the system. While out-of-plane forces and behavior
of the wall subjected to them may be important, it
is not important in rigidity calculations for
resisting in-plane forces.
FIGURE 1 SHEAR WALL
DEFLECTION
A cantilever shear wall
subjected to lateral load will deflect " ".
Considering flexural and shear deformations,
for a unit lateral load can be calculated
by:
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A = t x L where
for uncracked section.
t = thickness of wall
Ev = shear modulus = 0.4 Em
Substituting these values in the above
equation:

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Flexural
deformation
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Shear
Deformation
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Component
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Component
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Similarly for "piers" or
walls with top and bottom edges fixed against
rotation, " "
is given by:

Whether flexural
deformation governs or shear deformation
governs, is dependent on the
Ratio.
For a given wall, rigidity
therefore, the lesser the deflection, the more
rigid the wall. This can be intuitively seen by
imagining trying to deflect a wall in its own
plane. A higher
ratio will require less force to deflect the wall
than wall with a lower
ratio by the same amount.
FIGURE 2 MODES OF
DEFORMATION
Schematically, the modes of
deformation are shown in Figure 2.

As shown in Table 1, even for
squat walls, i. e., ,
flexural deformation is 57% of the total. Whereas
with a
ratio of 2.5, which is not uncommon in 2-3 story
tall buildings, flexural deformation is almost 90%
of the total deformation. The purpose of Table 1 is
to show the deformation multiplier, not to
calculate the actual deformation. To calculate
deformation, actual lateral load, Em and
t must be used. Table 1 is for cantilever walls. A
similar table could be developed for other
conditions.
TABLE 1 DEFORMATION
COMPONENTS
For Single story buildings
with long walls, where length between control
joints could be 1.5 times the height or
ratio of 0.67, shear deformation predominates and
flexural deformation concerns should be of less
importance.
Although failure in shear is
undesirable as it is considered non-ductile
(brittle), the behavior of the wall due to its
geometry cannot be changed. A well designed and
detailed wall for anticipated shear demand should
perform well.
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Influence of Openings on
Rigidity
As can be seen from the above
discussion, shear deformation is a function of
cross-sectional area of the wall for a given
height. Therefore in squat walls, openings will
reduce the cross-sectional area and the deflection
will increase proportionally as opening sizes
increase.
For flexure dominated walls,
since the deformation is a function of moment of
inertia, for a given height, the influence of
openings on deflection is less if located centrally
in the wall as the influence on reduction in moment
of inertia is minor.
We will consider two cases of
walls to demonstrate the effect of openings on the
rigidity:
1. where
= 0.67
2. where
= 1.5
Case 1: Wall with
= 0.67
Consider the following 8" CMU
solidly grouted wall.
Em = 1.5
ksi.
Ev = 0.6
ksi.
FIGURE 3. WALL ELEVATION
(CASE 1)

t = 7.625 inches
Substituting all the
values
For a 1K force, for a
solid wall,

Please note that 63%
of the deflection is due to shear.
Rsolid = 
Wall with
Opening
To account for the opening,
the wall can be split into three portions
,
and .
Since
is a beam with 8' 0" depth,
, it can be assumed that its behavior is
predominantly in shear and will offer fixity to
portions
and
at top.
The deflection of the wall is calculated below.
(The entire procedure is given in 1997 Design of
Reinforced Masonry Structures, published by
CMACN and is not repeated here.)

Please note 82%
of deflection is due to shear.

wall with openings =
wo
wo
=
solid -
solid strip +
piers
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8' 0" strip incorporating
opening

wo = 0.28 - 0.09 + 0.125
= 0.315 inches

Comparing the deflection of
solid wall with wall with opening, the deflection
is increased by 0.035 inches or 12.5%.
Now, if we consider that area
of the wall is reduced by 16.7% (4 ft. out of 24
ft.) and influence of shear deformation is
approximately 
The deflection is expected to
increase by 0.725 (16.7)
= 12.1%
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12.5%.
Therefore, without resorting
to detailed calculations, for walls with
ratio of 0.67, influence of opening can be judged
approximately by reduction in % of area for a
preliminary estimate. The calculation is closer to
the final number as
decreases.
It is important that in
final design, exact calculations should be
made.
Case 2: Wall with
= 1.5.
Consider the following 8"
solidly grouted wall with
Em = 1.5.ksi. and Ev = 0.6
ksi.
Consider the same opening
size as in Case 1. Since
= 1.5

FIGURE 4. WALL ELEVATION
(CASE 2)
wo
(wall with opening)
Following the previous
procedure:
wo
= T
- solid
strip + piers
solid
strip


piers


 


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The increase in deflection
due to opening is 0.14 inches (approximately
9%).
The decrease in area at base
is 25%. However, This is a flexure governing wall.
75% of deflection is due to flexure. So
approximation based upon reduction in area is not
correct.
However, since flexural
deflections are governed by "I," a quick
calculation of reduced moment of inertia will yield
better approximation for preliminary
purposes.
For a unit
thickness,


Reduction in moment of
inertia is only 1.5%.
However, since 75% is
flexural contribution, expected increase in
deflection = 0.75 x 0.015 = 0.0112, i.e.,
1.12%.
25% deflection is due to
shear contribution.
Expected increase in
deflection based on 25% reduction in area = 25% x
0.25 = 6.25%
Total expected increase in
deflection
= 6.25 + 1.12 = 7.37 %
»
9%.
Conclusions
This discussion on
deflection, and thus the rigidity of wall with
openings, provides an insight on influence of
flexural and shear deformations. The approximate
calculations are good enough for preliminary design
considerations.
One should keep in mind
ratio before the approximations are used.
Generally, the cutoff ratio between shear dominant
behavior and flexural dominant behavior is
= 1.0.
This issue of "Masonry
Chronicles" was written by Dr. Vilas Mujumdar,
Executive Director of CMACN.
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